A car goes around a vertical circle (Uniform Circular Motion)

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Homework Help Overview

The discussion revolves around a physics problem involving a remote-control car moving in a vertical circle. The participants are tasked with determining the normal force exerted on the car at two specific points in the circular path: the bottom and the top of the circle.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of force diagrams to analyze the forces acting on the car at different points in the vertical circle. There are attempts to apply Newton's second law and consider the effects of gravitational force and centripetal acceleration.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to calculate the normal force. Some guidance has been offered regarding the setup of force equations, but there is no explicit consensus on the correct method or final values yet.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a focus on understanding the differences in forces at the top and bottom of the circular path.

Chandasouk
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Homework Statement




A small remote-control car with a mass of 1.51 kg moves at a constant speed of v = 12.0 m/s in a vertical circle inside a hollow metal cylinder that has a radius of 5.00 m.

yf_Figure_05_76.jpg



What is the magnitude of the normal force exerted on the car by the walls of the cylinder at point A (at the bottom of the vertical circle)?

What is the magnitude of the normal force exerted on the car by the walls of the cylinder at point B (at the top of the vertical circle)?


Do I utilize Fnet = ma which would give me 43.488N as Fnet, but I do not see how that would help? I don't know what to do.
 
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Try drawing a force diagram when the car in at the bottom of the cylinder and when its
at the top of the cylinder.
 
For Part A, it would just be Fn pointing up and w pointing down.

w=mg so (1.51kg)(-9.8) = -14.798N so Fn must be 14.798N ?


Would part B basically be the same?
 
F_y = m*a_y
a_y = v^2/r

Does that help?
 
For part A it should be N - mg = 0, right ? Since mg is pointing down thus N has to be
pointing up.

For part B its not quite the same.
 

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