A car goes around a vertical circle (Uniform Circular Motion)

In summary: N = m*v^2/rIn summary, the conversation discusses the magnitude of the normal force exerted on a small remote-control car moving at a constant speed in a vertical circle inside a hollow metal cylinder. The formula Fnet = ma is mentioned, but it is not clear how it would help. The participants suggest drawing a force diagram and using the equations F_y = m*a_y and N = m*v^2/r to solve for the normal force at points A and B. Part A involves finding the normal force when the car is at the bottom of the circle, while Part B involves finding it at the top.
  • #1
Chandasouk
165
0

Homework Statement




A small remote-control car with a mass of 1.51 kg moves at a constant speed of v = 12.0 m/s in a vertical circle inside a hollow metal cylinder that has a radius of 5.00 m.

yf_Figure_05_76.jpg



What is the magnitude of the normal force exerted on the car by the walls of the cylinder at point A (at the bottom of the vertical circle)?

What is the magnitude of the normal force exerted on the car by the walls of the cylinder at point B (at the top of the vertical circle)?


Do I utilize Fnet = ma which would give me 43.488N as Fnet, but I do not see how that would help? I don't know what to do.
 
Physics news on Phys.org
  • #2
Try drawing a force diagram when the car in at the bottom of the cylinder and when its
at the top of the cylinder.
 
  • #3
For Part A, it would just be Fn pointing up and w pointing down.

w=mg so (1.51kg)(-9.8) = -14.798N so Fn must be 14.798N ?


Would part B basically be the same?
 
  • #4
F_y = m*a_y
a_y = v^2/r

Does that help?
 
  • #5
For part A it should be N - mg = 0, right ? Since mg is pointing down thus N has to be
pointing up.

For part B its not quite the same.
 

1. How does a car maintain its speed while going around a vertical circle?

The car maintains its speed by experiencing a constant centripetal force, provided by the friction between its tires and the road. This force keeps the car moving in a circular path with a constant speed.

2. What happens to the speed of the car as it goes around the vertical circle?

The speed of the car remains constant throughout the motion, as long as there are no external forces acting on it. This is because the centripetal force is always perpendicular to the car's velocity, causing no change in its speed.

3. How is the direction of the car's velocity changing as it goes around the vertical circle?

The car's velocity is constantly changing direction as it moves around the vertical circle. This is due to the centripetal force always being directed towards the center of the circle, causing the car to constantly change its direction of motion.

4. What is the relationship between the radius of the circle and the car's velocity?

The radius of the circle and the car's velocity are inversely proportional. This means that as the radius increases, the car's velocity decreases, and vice versa. This relationship is governed by the equation v = √(g*r), where v is the velocity, g is the acceleration due to gravity, and r is the radius of the circle.

5. Can a car go around a vertical circle without any external forces acting on it?

No, a car cannot go around a vertical circle without any external forces acting on it. This is because, in the absence of an external force, the car would move in a straight line, according to Newton's First Law of Motion. Therefore, the centripetal force is necessary to keep the car moving in a circular path.

Similar threads

  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
2
Replies
55
Views
649
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
28
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
2K
Back
Top