A charged capacitor when connected to uncharged one

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SUMMARY

A charged capacitor with a capacitance of 10 µF and a potential difference of 150V, when connected to an uncharged capacitor of 5 µF, results in a decrease in energy from 0.1125 J to 0.075 J. This energy loss occurs due to the dissipation of energy in the non-zero resistance of the connecting wires. The initial assumption that energy remains constant in both scenarios is incorrect; energy is lost when connecting capacitors of differing charge states.

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r0ss
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Homework Statement


A capacitor of capacitance 10 uF is raised to a potential difference of 150V. After disconnecting from the battery, it is connected to a capacitor of capacitance 5 uF. Find the energy of the system.

Homework Equations


Energy supposed to be equal in the first case and second case right? But the solution showed that the energy is decreased as the capacitor is connected with uncharged one. Which one is right?

The Attempt at a Solution


Solution for first assumption: 0.1125 J.
Solution for the second: 0.075 J.
 
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r0ss said:
Energy supposed to be equal in the first case and second case right? But the solution showed that the energy is decreased as the capacitor is connected with uncharged one. Which one is right?
There will be an energy loss, which is dissipated in the non-zero resistance of the connecting wires. If you search on Google saying "Energy losses on connecting two capacitors", you will get tons of results, like this one.
 
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