An uncharged capacitor is connected to a charged capacitor as shown:
The ends are left as it is.
Will the charges redistibute?
The Attempt at a Solution
I think it won't.
Let the first capacitor be charged with charge Q. Before closing the switch, the charges are like:
If ##x## charge flows from the negative plate of first capacitor to the second capacitor, then a same ##x## has to flow from the first plate as well since opposite faces of a capacitor should have charges of same magnitude. So no charge transfer is possible.
This, however, is the reason given in my textbook:
" The positive charge on one face of capacitor will hold the negative charge in place. "
Is it correct? Because if I were to connect the two free ends to each other, then also no charge should redistribute. (I am also thinking about the problem 3.2 from Prucell and Morin).