A Coordinates and Interval Question

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Homework Help Overview

The problem involves determining the coordinates of a particle after a specified time interval, given its initial coordinates and the assumption of constant velocity. The subject area pertains to kinematics and motion in two dimensions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss breaking down the problem into independent x and y components, using equations of motion for constant velocity. Questions arise regarding the interpretation of variables and how to apply the equations to the specific numerical values provided.

Discussion Status

There is an ongoing exploration of how to apply the equations of motion to the problem. Some participants express confusion about the application of the equations to their specific numbers, while others provide clarifications on the approach. Multiple interpretations of how to handle the time intervals and velocities are being considered.

Contextual Notes

Participants note the importance of understanding the relationship between distance, time, and velocity, especially as the problem may change with different time intervals. There is an acknowledgment of the learning curve associated with the concepts being discussed.

jenn047
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Homework Statement


During a 4.95 s interval, a particle's coordinates change from x = 10.4 m, y = 4.95 m to x = 31.5 m, y = -4.95 m. Assuming the particle's velocity is constant, what will its coordinates be at the end of the next 4.95 s interval?

x= ____m
y= ____m

Homework Equations


The Attempt at a Solution


My first thought was to take the x and y's given and find y=mx+b however I'm not sure that it is relevant or even helpful.

Thanks.
 
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You should consider both directions independently.

So x and y satisfy
x = u t + a,
y = v t + b

Equivalently, the distance covered in the second 4.95 seconds is the same as that covered in the first interval.
 
CompuChip,

I'm not sure I understand what you're saying. What do the variables represent in your equations? I'm sorry if these are silly questions, however I just finished my second day of Physics and am completely new to it (and also very bad at it!).
Thanks.
 
CompuChip is showing the equations of motion for a constant velocity. You can break the problem up into the orthogonal velocities in the x and y directions. So his first equation says that x(t) is equal to x(0) = a, plus an offset given by the velocity u multiplied by the time t.

Does that help?
 
berkeman,

I understand that much, however I don't understand how those equations work with my numbers?
 
jenn047 said:
berkeman,

I understand that much, however I don't understand how those equations work with my numbers?

You are given a delta-t and a delta-x and a delta-y. From those numbers and those equations, you can figure out what those constants are (u, a, v, b). With those constants and the next delta-t, you can figure out what the final positions will be after the second delta-t.
 
Thank you, I appreciate your time!
 
I definitely over analyzed the question. All you do is find the change in x and changed in y and add them to the last x and y coordinates. I didn't have to do anything with time or velocity.
 
In this case, yes, but what if the next interval was 6.1 seconds. Profs have bbeen known to do such things, esp physics profs!:smile:


So knowing the velocities is a necessary skill on the third day.
 

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