What is the Maximum Temperature for a Copper Block at 1000 atm Pressure?

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Homework Help Overview

The problem involves a block of copper subjected to varying temperatures and pressures, specifically examining the relationship between temperature and pressure at constant volume. The context includes calculations related to thermal expansivity and isothermal compressibility, with a focus on determining the maximum temperature achievable under a pressure constraint of 1000 atm.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the formula relating pressure and temperature changes, questioning the calculations for both parts of the problem. There is an exploration of the initial conditions and assumptions regarding thermal properties.

Discussion Status

Some participants have provided calculations for part (a) and noted discrepancies in the expected results for part (b). There is an ongoing examination of the assumptions made regarding the initial conditions and the implications for the maximum temperature calculation.

Contextual Notes

Participants highlight that the volume expansivity and isothermal compressibility values are assumed to remain constant within a specified temperature range, which may influence the calculations. There is also a note on the pressure limit of 1000 atm and its implications for the final temperature.

Muthumanimaran
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Homework Statement


(a) A block of copper at a pressure of 1 atm and a temperature of 5 degree celcuis is kept at constant volume. If the temperature is raised to 10 degree celsius what will be the final pressure?

(b) If the vessel holding the block of copper has a negligibly small thermal expansivity and can withstand a maximum pressure of 1000atm, what is the highest temperature to which the system may be raised?

(Note: The volume expansivity and isothermal compressiblity are not always listed in handbooks of data. However, volume expansivity is three times the linear expansion coefficient and isothermal compressibility is reciprocal of the bulk modulus. For this problem, assume that volume expansivity and isothermal compressibility remain practically constant within the temperature range of 0 to 20 degree celsius at the values of 4.95 x 10^(-5) K^-1 and 6.17 x 10^(-12))

Homework Equations


(Pf-Pi)=(volume expansivity / isothermal compressibility) (Tf-Ti)

The Attempt at a Solution


part (a) of the problem can be easily done by using by substituting the given data in the formula above.
$$P_{f}-P_{i}=\frac{\beta}{\kappa}(T_{f}-T_{i})$$
$$P_{f}-10^{5}=\frac{4.95 \times 10^{-5}}{6.17 \times 10^{-12}} (10-5)$$
gives Pf=40200 Pa

If I do the same for part (b) by taking initial temperature as 0 degree celsius and initial pressure as 1 atm, the final temperature is 2.4 degree celsius but the correct answer is 17 celsius, give me a hint.
 
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What answer to you get for part (a)? Also, please show your calculations.
 
DrClaude said:
What answer to you get for part (a)? Also, please show your calculations.
$$P_{f}-P_{i}=\frac{\beta}{\kappa}(T_{f}-T_{i})$$
$$P_{f}-10^{5}=\frac{4.95 \times 10^{-5}}{6.17 \times 10^{-12}} (10-5)$$
gives Pf=40200 Pa
 
Muthumanimaran said:
Pf=40200 Pa
You are off by a few orders of magnitude.

In any case, your result for Tf = 10 °C is Pf < 1000 atm. How can you get a temperature of 2.4 °C for 1000 atm?
 

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