A cube of some substance floats

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A cube of unknown material floats in mercury, with 43% of its volume above the surface and 57% submerged. The density of mercury is established at 13,594 kg/m³. Using the principle of buoyancy, it is determined that the cube's density is 57% of that of mercury. This leads to the conclusion that the density of the cube is approximately 7,747.58 kg/m³. The calculations confirm that the cube's weight is equivalent to 57% of the weight of the displaced mercury.
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Homework Statement


A cube of some unknown material floats in a pool of mercury. 43% of the cube is above the surface. Find the density of the cube.

Homework Equations


Fb=pVg
d=m/V

The Attempt at a Solution


So I Googled the density of mercury and found that it is 13,594 kg/m3. I also know that 57% of the cube is underwater.

mg=pVg
m=pV
m=p(.57V)

d=m/V
d=p(.57V)/V
d=.57pHg

Is that correct?
 
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That is correct. If an object displaces 57% of the weight of mercury then that means it's own weight is 57% of that of the weight of mercury in the same volume. This means then that it's density is 57% that of mercury.
 
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