- #1

Nanu Nana

- 95

- 5

## Homework Statement

A person (with mass 60.0 kg) is located on a volume of ice, floating on the water. Calculate the smallest volume of the ice so that the person would remain above the water ( ice density = 917kg / m3)[/B]

## Homework Equations

F= m xg

Archimedes F = density x V xg [/B]

## The Attempt at a Solution

If the object is floating then we know that F(g) = F(a)

therefore

m xg = d x V x g

g cancels out

m = d x v

60kg= d (ice) x V

V= 60kg / 917 kg/m3

V = 0.065 m 3

But the answer should be 0.72 m3 [/B]

**Thank you :)**