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All of this is true, but it still does not tell us the specific form of the states ##\ket{l, m}##. It's just restating the fact that those states, whatever they are, are eigenstates of ##H## with particular eigenvalues. That's not enough by itself to address the questions you've been asking about the dependence of the states ##\ket{l, m}## on the coordinates. For that we need to know the specific form of those states, which will depend on the specific form of ##H##.hokhani said:Since ##[H,L^2]=0## we have ##L^2H|l,m\rangle=HL^2|l,m\rangle=l(l+1)H|l,m\rangle##. So, ##H|l,m\rangle## is an eigenstate of ##L^2## with eigenvalue ##l(l+1)## and so it is linear combination of ##|l,m\rangle## as ##H|l,m\rangle=\sum_m \alpha_m |l,m\rangle##. Similarly, since ##[H,L_z]=0## we would have ##H|l,m\rangle=\sum_l \beta_l |l,m\rangle##.