A derivation of the Vdc in a fullwave rectifier with smoothing?

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Homework Help Overview

The discussion revolves around deriving the Vdc in a full-wave rectifier with a smoothing capacitor, focusing on the assumptions and approximations involved in the derivation process.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the Vdc and questions the validity of assuming it as the average of the discharging function. Other participants discuss the implications of this assumption and the factors affecting charge and discharge times.

Discussion Status

Some guidance has been offered regarding the appropriateness of the assumption made by the original poster, with acknowledgment of additional factors that may influence the charge time in the rectifier circuit.

Contextual Notes

Participants note that the diode resistances are significantly smaller than the load resistance, which affects the charge-up and discharge times. There is also mention of other factors such as diode forward voltage drops and transformer characteristics that may play a role in the derivation.

patric44
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Homework Statement
i had an assignment of deriving the Vdc in a fullwave rectifier with smoothing capacitor
Relevant Equations
Vdc = V average of the discharging part
i was trying to derive the Vdc in a fullwave rectifier with smoothing capacitor , i guess i had it right as my final equation matches the book equation :

Vdc~(1-(1/2fRC))Vp , but i am not really sure that my attempt was completely right as i assumed that Vdc is the average value of the discharging function neglecting the charging part , and i had to take the first 3 terms of the Taylor approximation to get the answer ,
i just want some one to verify my attempt :
capacitor.png

cap33.jpg
 
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Any help , i will really appreciate it
 
Last edited:
i just want to know if assuming that the vdc is the average of the discharging function is a good approximation
or not .
r9MqF.gif
 

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Yes it is. The diode resistances are very much smaller than the load resistance so the charge-up time is very small compared to the discharge time.

But the charge time is not zero, and depends not only on diode forward voltage drops but also transformer winding resistances. and leakage inductances.
 

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