A different loop-de-loop assignment

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Homework Help Overview

The discussion revolves around a physics problem related to a loop-de-loop scenario, specifically focusing on calculating the speed of a ball after it exits the loop. The original poster presents initial data, including the radius of the loop, the mass of the ball, and its speed upon entering the loop.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the relationship between the height of the loop and the speed of the ball at various points. Questions are raised about the definition of the "end" of the loop and its height relative to the entry point speed.

Discussion Status

The discussion is ongoing, with participants questioning the mechanical energy of the ball as it returns to the same height. There is an exploration of the implications of energy conservation in this context.

Contextual Notes

Participants note the lack of guidance from the teacher and the absence of similar examples in the course material, which may be influencing their approach to the problem.

riddledum
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My physics teacher gave us this follow-up to the classic loop-de-loop assignment where you have to calculate the height from where you have to drop a ball in order for it to just make it round the loop. The problem with this assignment is that our teacher refuses to help us, and there are no similar examples in our coursebook.

This time, he asked us to calculate the speed of the ball after it comes out of the loop. Here are some of the data I've collected so far:

The loop has a radius of 0.0675 cm
The ball weighs 0.0282 kg
The speed of the ball is 2.16 m/s when it enters the loop

I've have done some calculations, and got the speed at the top of the loop to 1.42 m/s, which seems plausible, but I have no idea how to get the speed at the end of the loop.
 
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What does the "end" of the loop look like? How high is it relative to the point where the speed is 2.16 m/s? Do you see what I am getting at?
 
kuruman said:
What does the "end" of the loop look like? How high is it relative to the point where the speed is 2.16 m/s? Do you see what I am getting at?

The whole thing looks like this:

[URL]http://pici.se/pictures/mnClqYBkT.jpg[/URL]

The end is at the same height as the point where the velocity of the ball is 2.16 m/s
 
Last edited by a moderator:
Has the ball lost any mechanical energy when it returns to the same height at which it had a speed of 2.16 m/s?
 

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