A differential geometry question

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The discussion centers on proving that the normal vector function n(s) of a unit-speed curve with non-zero torsion determines both curvature and torsion. Participants express confusion about how to compute curvature and torsion solely from the normal vector, given that these are typically defined in relation to the tangent vector. The curvature is defined as the magnitude of the second derivative of the position vector, while torsion is linked to the normal and binormal vectors. There is a suggestion to utilize the Frenet-Serre frames to aid in the calculations. Overall, the thread highlights the challenge of deriving curvature and torsion from limited information about the normal vector.
binglee
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Show that the knowledge of the vector function n = n(s) (normal vector) of a unit-speed
curve
, with non-zero torsion everywhere, determines the curvature and the torsion
don't have any clues about what i am supposed to prove!~
 
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You are supposed to compute the curvature and torsion of a curve from its normal vector function. You probably defined curvature and torsion as a function of the tangent vector.
 
ya, we defined curvature = ||r''||=||t'||. It is a function of t, while we defined torsion = -n.b' it is not a function of t. I don't know if my understanding about torsion is right. Since we defined n as a function of t and b as a function of t so is t. Then in this question i just need to go through the same process wrt n??right? thank you for your helping
 
bump can anybody help me?!~~~~
I thought about it for a while. what does it mean by the knowledge of n?
if we know t n b, we can determine the curvature and the torsion, but here we only know n??
please!~ help me!~~
 
binglee:

Have you tried working with Frenet-Serre frames.?
 

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