A dimensional analysis problem.

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SUMMARY

The discussion centers on a dimensional analysis problem involving the conversion of units from eV/A² to THz² using the constant 1/mass. The user correctly identifies that mass should be expressed in MeV/c² and that Angstroms (A) represent a length unit. The calculations confirm that the reciprocal of mass in the specified units yields c²/eV, leading to the conclusion that the final result simplifies to Hz². This confirms the user's approach to the problem is accurate.

PREREQUISITES
  • Understanding of dimensional analysis in physics
  • Familiarity with energy units such as eV and MeV
  • Knowledge of the speed of light (c) and its role in unit conversions
  • Basic grasp of frequency units, specifically THz and Hz
NEXT STEPS
  • Study the principles of dimensional analysis in physics
  • Learn about unit conversions involving energy and mass
  • Explore the relationship between frequency and wavelength in the context of THz
  • Investigate the implications of using Angstroms in physical calculations
USEFUL FOR

Students and professionals in physics, particularly those working on problems involving unit conversions and dimensional analysis in particle physics or quantum mechanics.

lylos
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Homework Statement


Basically, I have a constant that is 1/mass. I need to find out how to relate this to my function which has units eV/A^2 to have results in THz^2.

Homework Equations


The Attempt at a Solution


I think I would just have the mass in units of MeV/c^2 and then convert c^2 into A^2/s^2... Does this sound correct?
 
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I think that will work, since A seems to be a length unit (Angstroms?) from what you say.

Let's see ... reciprocal of mass in your units would be c^2/eV, so:

[tex] \frac{c^2}{eV} \cdot \frac{eV}{A^2}<br /> = \frac{A^2}{s^2 \cdot eV} \cdot \frac{eV}{A^2}<br /> = \frac{1}{s^2}<br /> = Hz^2[/tex]
 
Redbelly98 said:
I think that will work, since A seems to be a length unit (Angstroms?) from what you say.

Let's see ... reciprocal of mass in your units would be c^2/eV, so:

[tex] \frac{c^2}{eV} \cdot \frac{eV}{A^2}<br /> = \frac{A^2}{s^2 \cdot eV} \cdot \frac{eV}{A^2}<br /> = \frac{1}{s^2}<br /> = Hz^2[/tex]

Yeah, it was Angstroms. That's what I was thinking it would be, was just wanting to run it through with someone else before I started over again. Thanks. :)
 

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