A doubt from rigid body dynamics

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SUMMARY

The discussion centers on the relationship between the velocity of the center of mass (vcm) and the velocity of any particle (vp) in rigid body dynamics, expressed as vcm = vp + r × ω. Here, r represents the position vector of the particle relative to the center of mass. The participants also explore the calculation of angular velocity (ω) using the formula ω = (v × r) / r², clarifying that v refers to the linear velocity of the particle.

PREREQUISITES
  • Understanding of rigid body dynamics principles
  • Familiarity with vector mathematics
  • Knowledge of angular velocity concepts
  • Basic grasp of kinematics
NEXT STEPS
  • Study the derivation of the center of mass in rigid body dynamics
  • Learn about vector cross product applications in physics
  • Explore advanced topics in angular momentum
  • Investigate the implications of rigid body motion in engineering
USEFUL FOR

Physics students, mechanical engineers, and anyone studying dynamics and motion of rigid bodies will benefit from this discussion.

vijayramakrishnan
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in rigid body dynamics is this relation between velocity of centre of mas and velocity of any particle in the rigid body correct?
vcm = vp + rXω

r is the position vector of the particle with respect to centre of mass

relations are written in vector form and also tell me how to calculate direction of ω.
 
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ω=(v × r) /r^2
 
tade said:
ω=(v × r) /r^2
what is v here sir?
 

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