A doubt regarding vectors, scalars and their role in physics

Click For Summary
SUMMARY

This discussion clarifies the classification of physical quantities as vectors or scalars and the implications of this classification in classical and relativistic mechanics. It establishes that there are no guarantees that every measured quantity can be classified strictly as a vector or scalar, as these classifications are based on axioms and postulates that are subject to experimental validation. The conversation highlights that scalars and vectors correspond to zero- and first-order tensors, respectively, and introduces the concept of higher-order tensors, such as the stress tensor, which are also essential in physics and engineering.

PREREQUISITES
  • Understanding of classical mechanics principles
  • Familiarity with the concepts of vectors and scalars
  • Basic knowledge of tensor mathematics
  • Awareness of relativistic mechanics implications
NEXT STEPS
  • Research the role of higher-order tensors in physics, specifically the stress tensor
  • Study the axioms and postulates of classical mechanics
  • Explore the differences between classical and relativistic mechanics
  • Learn about tensor calculus and its applications in engineering
USEFUL FOR

Students and professionals in physics and engineering, particularly those interested in the mathematical foundations of physical laws and the application of tensors in various fields.

JackFyre
Messages
15
Reaction score
7
TL;DR
A doubt regarding vectors, scalars and their role in physics
I have a doubt regarding the basic function of vectors and scalars in physics-

What is the guarantee that every quantity(measured) in physics can be classified as either a vector or a scalar, and that while performing operations on said quantities, they will obey the already established rules of vector/scalar operations?
 
Physics news on Phys.org
JackFyre said:
What is the guarantee that every quantity(measured) in physics can be classified as either a vector or a scalar, and that while performing operations on said quantities, they will obey the already established rules of vector/scalar operations?

zero... zero guarantees... It just seems to do quite alright considering what we've achieved by using them. What do you suggest as alternative?
 
  • Like
Likes   Reactions: JackFyre
JackFyre said:
Summary:: A doubt regarding vectors, scalars and their role in physics

I have a doubt regarding the basic function of vectors and scalars in physics-

What is the guarantee that every quantity(measured) in physics can be classified as either a vector or a scalar, and that while performing operations on said quantities, they will obey the already established rules of vector/scalar operations?
Can you be more precise about your question?

It's generally implied in classical physics that if we have two particles of mass ##m_1## and ##m_2## and we put them together, then we have a system of mass ##m = m_1 + m_2##.

There's no guarantee that will be correct. It's more an axiom or postulate of classical mechanics that gets tested (along with all the other axioms, postulates or laws of motion) during an experiment.

And, in fact, in relativistic mechanics if ##m## above represents rest mass, then it's not true. For example, if ##m_e## is the mass of an electron and ##m_p## the mass of a proton, and ##m## is the mass of a hydrogen atom with one proton and one electron, then: ##m \ne m_p + m_e##.
 
  • Like
Likes   Reactions: vanhees71
PeroK said:
Can you be more precise about your question?

It's generally implied in classical physics that if we have two particles of mass ##m_1## and ##m_2## and we put them together, then we have a system of mass ##m = m_1 + m_2##.

There's no guarantee that will be correct. It's more an axiom or postulate of classical mechanics that gets tested (along with all the other axioms, postulates or laws of motion) during an experiment.

And, in fact, in relativistic mechanics if ##m## above represents rest mass, then it's not true. For example, if ##m_e## is the mass of an electron and ##m_p## the mass of a proton, and ##m## is the mass of a hydrogen atom with one proton and one electron, then: ##m \ne m_p + m_e##.
That pretty much answers it, thanks!
 
Scalars and vectors are just zero- and first order tensors, respectively. In physics and engineering we also need to employ higher order tensors, such as the stress tensor.
 
  • Like
Likes   Reactions: vanhees71

Similar threads

  • · Replies 50 ·
2
Replies
50
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 35 ·
2
Replies
35
Views
5K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 16 ·
Replies
16
Views
6K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K