A gradient field (analysing a picture)

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Homework Help Overview

The discussion revolves around analyzing a gradient field based on a provided picture and understanding how the function value changes as one moves within that field. The context involves concepts from vector calculus, specifically relating to gradient functions and level curves.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to interpret the relationship between the gradient field and the function values as one moves through the field. Questions about the complete problem statement and the implications of the gradient's direction are raised.

Discussion Status

Some participants have expressed agreement on the interpretation of the gradient's effect on the function value, noting that moving in the direction of the gradient results in an increase in the function value. However, the discussion remains open with questions about the initial problem statement and the specific function being analyzed.

Contextual Notes

There is a mention of a missing function definition, which may limit the depth of analysis. The discussion also references a specific point in the gradient field, indicating a focus on local behavior rather than a global understanding.

Poetria
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Homework Statement
The gradient of the function f.
R - the region inside and on the boundary of the circle.
You start at the point (1,-1) and move slightly to the right. How does the value of f change?
Relevant Equations
The function has its maximum at the point (0, -2)
Gradient-field.jpg
I think it is increasing as you move from one level curve to the other with bigger value. Am I right?
 
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Explain the relationship with the picture -- if any

What is the complete problem statement ?
 
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Well, you have the picture I have posted. And you should answer the question I have posted. The function isn't given.

"Here is a picture of the gradient of a function f . Let R denote the region inside and on the boundary of the circle."
"If you start at the point (1, -1) and move slightly to the right, how does the value of f change?
 
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I agree with your answer. The gradient has a component in your direction going to the right, so the function value is increasing slightly as you move right.
 
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FactChecker said:
I agree with your answer. The gradient has a component in your direction going to the right, so the function value is increasing slightly as you move right.
Great. :) Thank you very much. :)
 

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