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Unit vector perpendicular to the level curve at point

  1. Feb 16, 2017 #1
    1. The problem statement, all variables and given/known data
    Find the unit vector perpendicular to the level curve of f(x,y) = x2y-10xy-9y2 at (2,-1)

    2. Relevant equations
    Gradient

    3. The attempt at a solution
    I'm not sure what it's asking. Wouldn't this just be the gradient of f(x,y) evaluated at (2,-1) then normalized? or am I missing something?
     
  2. jcsd
  3. Feb 17, 2017 #2

    Orodruin

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    Yes. Is that a problem?
     
  4. Feb 20, 2017 #3
    No problem at all. I just wasn't sure what a level curve was.
     
  5. Feb 20, 2017 #4

    Orodruin

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    A level curve of a function is the curve such that the function takes a fixed value. For example, the level curves of f=x^2+y^2 are circles.
     
  6. Feb 20, 2017 #5
    Oh that makes much more sense. Thank you.
     
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