A GRAVITATIONAL POTENTIAL ENERGY questions

In summary, the question is asking for the amount of work required to move a satellite from an orbital radius of 2r_e to 3r_e, given its mass of 500 kg. The solution in the book does not consider the change in kinetic energy, while the attempt by the individual asking the question includes it. Upon further clarification, it is determined that the book's solution is correct as work is the difference between two energy states. A second question is also posed regarding the minimum time for a satellite to orbit the Earth, but it is found that the given information is not sufficient to solve the problem.
  • #1
rootX
479
4

Homework Statement


determine the amount of work required to move a satellite from orbital radius of
2r_e (twice the radius of the earth) to 3r_e, if it has a mass of 500 kg?


Homework Equations


Find change in Gravitation potential energy
and also the change in the kinetic energy

The Attempt at a Solution



The solution is the book does not consider the change in the kinetic energy. Shouldn't it be considered as velocity is decreased when it moves to a higher orbit
 
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  • #2
What is the relationship between either Work or Potentential energy and Kinetic? You didn't show your relavant equations. Show your attempt also
 
  • #3
it's simple though
W = change in U + change in E_k
<I solved that question using this method>
and, the book solved it using
W= change in U

yea, i didn't show my work because I have the solution provided in the book, so I am just confused about how the book solved it
 
  • #4
what is the relationship between potential energy and kinetic? Would it make a difference if you write the change in potential or change in kinetic? It applies to what kind of question you are solving. You did not give us the exact problem you are asking, you did not give us all the relavant equations, you did not show us any of your work. Do you want to solve the problem?
 
  • #5
hmm.. certainly

so, here's my exact question:
determine the amount of work required to move a satellite from orbital radius of
2r_e (twice the radius of the earth) to 3r_e, if it has a mass of 500 kg?

as for relevant equations <they are just too messy>
E_k = 0.5mv^2
E_g = - (GMm)/r

and here's the attempt
Work = - (GMm)/r_f + - (GMm)/r_i + 0.5mv_f^2 - 0.5mv_i^2

v^2 = GM/r
0.5mv^2 = 0.5xGMm/r

so
Work = - (GMm)/r_f + (GMm)/r_i + 0.5(GMm)/r_f - 0.5(GMm)/r_i

Work = -0.5(GMm)/r_f + 0.5(GMm)/r_i

so, it is equal to 0.5(GMm)[1/r_i - 1/r_f]

so this is how i did it
but the book did it this way
Work = - (GMm)/r_f + (GMm)/r_i
 
  • #6
rootX said:
hmm.. certainly



so this is how i did it
but the book did it this way
Work = - (GMm)/r_f + (GMm)/r_i

Looks like the book did it correctly, Work is the difference between two energy states. Is that clearer? Work is transfer of energy. So you can say it is the difference of two inergy states. initial and final. How much work does it take to lift a object vertically up? Did the object change in potential energy? Also, when you look at a problem, see what they give you, and that is all you know. Given what they gave you, is it most logical to solve it the book way?
 
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  • #7
yea,i understand the concepts of work

How much work does it take to lift a object vertically up?
but isn't this situation different, because initially the object is moving perpendicular to the applied force, and in its final state, it moving with a lower velocity, thus this decreased the kinetic energy. This happens along with the change in the gravitational potential energy.
 
  • #8
rootX said:
yea,i understand the concepts of work

How much work does it take to lift a object vertically up?
but isn't this situation different, because initially the object is moving perpendicular to the applied force, and in its final state, it moving with a lower velocity, thus this decreased the kinetic energy. This happens along with the change in the gravitational potential energy.

Read the question carefully, it says to move the satillite from one position to another. Did the problem give you velocity? If want to solve it using work-kinetic, be my guest. If they didn't give you the right pieces of the puzzle, how can you solve it?
 
  • #9
I solved for v using that equation

Centripetal force = gravitational force

(mv^2)/r = (MmG)/r^2
<cuz it's orbiting>
anyhow, now I got the question --> "from one position to another."

now, this is my second question
Prove that “No satellite can orbit Earth in less than about 80 min”?
yes, i can do this numerically, and I have done that, and it gives minimum time of 85 min

But, since they didn't mention anything about forces, so anyone can supply more downward force<towards the center of the earth>, so as to lower the time period.
 
  • #10
rootX said:
I solved for v using that equation

Centripetal force = gravitational force

(mv^2)/r = (MmG)/r^2
<cuz it's orbiting>
anyhow, now I got the question --> "from one position to another."

now, this is my second question
Prove that “No satellite can orbit Earth in less than about 80 min”?
yes, i can do this numerically, and I have done that, and it gives minimum time of 85 min

But, since they didn't mention anything about forces, so anyone can supply more downward force<towards the center of the earth>, so as to lower the time period.

Yeah, but that is velocity in its orbit. That is not radial movement. Radial positions. Distance from earth. Let's say you are running with velocity and holding and object on top of your hand, you lift it up. is it the same amount of work if you were not in motion? Work on the object.
 
Last edited:

1. What is gravitational potential energy?

Gravitational potential energy is the energy stored in an object due to its position in a gravitational field. It is the potential for an object to do work when it is moved from its current position to a lower position.

2. How is gravitational potential energy calculated?

The formula for gravitational potential energy is PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object relative to a reference point. This formula assumes a constant gravitational field, such as near the surface of the Earth.

3. What factors affect gravitational potential energy?

The three main factors that affect gravitational potential energy are the mass of the object, the strength of the gravitational field, and the height of the object. The greater the mass and the height, and the stronger the gravitational field, the higher the potential energy.

4. Does gravitational potential energy vary with location?

Yes, gravitational potential energy varies with location since the strength of the gravitational field can vary depending on the distance from a massive object. For example, an object placed on the surface of the Earth will have a higher potential energy than the same object placed at a higher altitude.

5. What is the relationship between kinetic energy and gravitational potential energy?

Gravitational potential energy and kinetic energy are both forms of mechanical energy and are interconvertible. As an object falls, its potential energy decreases while its kinetic energy increases, and vice versa. At the bottom of its fall, all of the potential energy is converted into kinetic energy.

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