A gun that fires charged particles accelerates a 5-μC charge from rest through a potential difference of 50,000 V. The particle has a mass of 0.025 kg. With what speed does it leave the gun?
EPE = KE
(1/2)qV = (1/2)mv^2 , solve for v^2
The Attempt at a Solution
EPE = (1/2) x (5^-6 Coulombs) x (50,000 Volts)
KE = (1/2) x ( 0.025kg) x (v^2)
where the problem lies:
When i solve for velocity i get 3.16 m/s, however the answer my teacher gave to this problem was 4.5 m/s. Am i missing something here??