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fight_club_alum

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## Homework Statement

28. Particle A (mass = m, charge = Q) and B (mass = m, charge = 5 Q) are released from rest

with the distance between them equal to 1.0 m. If Q = 12 μC, what is the kinetic energy of

particle B at the instant when the particles are 3.0 m apart?

a . 8.6 J

b. 3.8 J

c. 6.0 J

d. 2.2 J

e. 4.3 J

## Homework Equations

(delta (u) = delta ke

## The Attempt at a Solution

(k*(Q*10^-6)*(5Q*10^-6))/1) - (k*(Q*10^-6)*(5Q*10^-6))/3) = 4.3152

4.3152 = u1 + u2 <-- I want u2 alone since the initial kinetic energy is zero

5u1 = u2

4.3152 = u1 + 5u1

4.3152 = 6u1

u1 = 0.7192

(5*0.7192) = 3.596 ~ 3.6 <-- not the right answer, it should be d

Any help, please?

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