A Kirchhoff problem: Find the currents and voltages in this circuit

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SUMMARY

The discussion focuses on solving a Kirchhoff circuit problem involving the calculation of currents I1, I2, I3, I4, I5, and the voltage Ug. The participant successfully determined that I2 equals 5 A and I4 equals -15 A, while encountering difficulties with the equations for I1 and I3. The equations utilized include superposition and Kirchhoff's laws, highlighting the importance of rearranging circuit components for clarity in analysis.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic knowledge of circuit analysis techniques
  • Proficiency in solving linear equations
NEXT STEPS
  • Study advanced circuit analysis using Thevenin's and Norton's theorems
  • Learn about mesh and nodal analysis techniques
  • Explore practical applications of Kirchhoff's laws in real-world circuits
  • Practice solving complex circuit problems with multiple loops and nodes
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in circuit analysis and problem-solving using Kirchhoff's laws.

Guillem_dlc
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Homework Statement


In the circuit of the figure, determine the intensities I1, I2, I3, I4, I5 and the voltage Ug.

Homework Equations


Superposition and Kirchoff

The Attempt at a Solution


20-10I1+5I3-10I1=0
5I3+Ug+5I5=0
20I2+10I2-150=0

From the last equation, 30I2 = 150, I2 = 5 A

KNOTS:

-10-I4-5=0 I4=-15 A

-I5+(-15)+5=0 I5=-10 A

System of knot equations of I3 and I5 does not work

-10-I1-I3=0
I3+I1-10=0

I3=-10-I1
-10-I1+I1-10=0 -20≠0

Here I have stayed, the part of the left is what resists me
 
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Guillem_dlc said:
In the circuit of the figure
 
Here it is:
 

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Have you considered rearranging the right hand side of the circuit temporarily?
 

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Okay I try so, thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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