- #1
- 4
- 0
Homework Statement
A mass of 1x10^-16 kg is traveling at 0.5 c to the nearest hundredth joule what is its kinetic energy?
Homework Equations
Et=KE + mc^2=Jmc^2
KE=mc^2(J-1)
KE=mc^2(1/sqrt(1-v^2/c^2)-1)=
The Attempt at a Solution
This is where i am stuck putting the whole thing in the calculator i guess...
(1X10^-16)(.5)^2(1x10^-16)(3x10^8)^2(1/sqrt(1-0.5^2)^2-1)
answer is 1.39, i keep getting something else?