- #1

xterminal01

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## Homework Statement

A mass of 1x10^-16 kg is traveling at 0.5 c to the nearest hundredth joule what is its kinetic energy?

## Homework Equations

Et=KE + mc^2=Jmc^2

KE=mc^2(J-1)

KE=mc^2(1/sqrt(1-v^2/c^2)-1)=

## The Attempt at a Solution

This is where i am stuck putting the whole thing in the calculator i guess...

(1X10^-16)(.5)^2(1x10^-16)(3x10^8)^2(1/sqrt(1-0.5^2)^2-1)

answer is 1.39, i keep getting something else?