Finding relativistic mass and energy of an electron

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Homework Help Overview

The discussion revolves around calculating the relativistic mass and energy of an electron that has been accelerated to half the speed of light. Participants are exploring concepts related to relativistic physics, particularly focusing on the equations governing mass and energy in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to calculate kinetic energy, relativistic mass, and total energy using various equations. There is a discussion about the role of the Lorentz factor (gamma) in these calculations, with some participants questioning their understanding of its implications and how it relates to rest mass.

Discussion Status

The conversation is ongoing, with participants providing guidance on the use of gamma and its relationship to relativistic mass. There are multiple interpretations being explored regarding the equations and their applications, particularly concerning kinetic and total energy calculations.

Contextual Notes

Some participants express uncertainty about their prior knowledge of relativistic concepts, indicating a potential gap in understanding the foundational principles of relativistic mass and energy. There is also mention of external resources for further clarification.

AlexPilk
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Homework Statement



A resting electron was sped up to 0.5 of the speed of light. Find:
A. relativistic mass of the electron,
B. total energy of the electron,
C. kinetic energy of the electron.

Homework Equations


K = mv^2/2
E=mc^2

The Attempt at a Solution


Let’s first find the kinetic energy:
K = m*v^2/2
K = (9.1*10^-31*0.25*9*10^16)/2 = 1.02375*10^-14 J

Now we should find relativistic mass using E=mc^2.
m(rel) = E/c^2 = (1.02375*10^-14)/(9*10^16) = 1.1375*10^-31 kg

Total energy must be = m(rest)*c^2
Then E(total) = 9.1*10^-31*9*10^16 = 8.19*10^-14 J

Is this solution correct?
And I suppose potential energy = 8.19*10^-14 - 1.02375*10^-14 = 7.16625*10^-14 ? :)
 
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No, that is not correct. Do you have an equation with rest mass and Gamma (which is a relationship that crops up a lot in relativistic formula)?
 
rpthomps said:
No, that is not correct. Do you have an equation with rest mass and Gamma (which is a relationship that crops up a lot in relativistic formula)?
I'm not sure what equation you mean. I found p = mv*gamma, but I don't understand what gamma means there.
 
This is gamma

##\gamma =\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}##
 
You were never taught this?
 
rpthomps said:
You were never taught this?
I have a ton of stuff to figure out by myself in a short period of time, so sorry for stupid questions :( I don't remember anything about relativistic mass from school.
So gamma is also relativistic mass/rest mass?
 
Its not a stupid question, I am just wondering what you know about mass at relativistic speeds. Check out the article I sent, there is a ratio embedded in there that you will find useful. :)
 
rpthomps said:
Its not a stupid question, I am just wondering what you know about mass at relativistic speeds. Check out the article I sent, there is a ratio embedded in there that you will find useful. :)
Ok, then m(rel) = gamma*m(rest)
gamma = sqrt(1-0.25) = sqrt(0.75)
m(rel) = sqrt(0.75)*9.1*10^-31 = 7.88*10^-31

Is it correct now?
 
  • #10
Gamma is almost like a way of translating mass/lengths/time from the ordinary or Newtonian way of thinking of life to the relativistic way... It's usually a multiplier of some kind.
 
  • #11
AlexPilk said:
Ok, then m(rel) = gamma*m(rest)
gamma = sqrt(1-0.25) = sqrt(0.75)
m(rel) = sqrt(0.75)*9.1*10^-31 = 7.88*10^-31

Is it correct now?

You are close. It should be m_electron/sqrt(0.75)
 
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  • #12
rpthomps said:
You are close. It should be m_electron/sqrt(0.75)
Hm, but why? On wikipedia the equation is m(rel)/m(rest) = gamma, so gamma*m(rest) = m(rel)
 
  • #13
rpthomps said:
This is gamma

##\gamma =\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}##

Mass increases as speed increases
 
  • #14
rpthomps said:
Mass increases as speed increases
Right, got it. So then I should plug in relativistic mass as m into K = mv^2/2 and E=mc^2 and get the kinetic and total energies?
Then m = 9.1*10^-31/sqrt(75) = 1.05 * 10^-30
Total energy E = 1.05*10^-30*9*10^16 = 9.45*10^-14
Kinetic energy K = (1.05*10^-30*0.25*9*10^8)/2 = 1.18*10^-22

Or am I wrong again?
 
  • #15
Oh, looked it up. KE = mc^2 - m0c^2 = 1.05*10^-30*9*10^16 - 9.1*10^-31*9*10^16 = 1.26*10^-14 J
Now I have to figure what "total energy" means.
KE = Total energy - Potential energy, so I suppose m(rel)*c^2 = 9.45*10^-14 is total energy like I wrote in the previous message? I hope it's correct now? :)
 

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