A mass on a spring, trying to find dispacement after at certain time. ( )

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SUMMARY

The discussion focuses on calculating the displacement of a mass-spring system after a specified time. A 0.27 kg mass is suspended on a spring, stretching it 4.9 cm to reach equilibrium. The mass is then pulled down an additional 12.5 cm and released. The key equations for simple harmonic motion (SHM) are presented, including x(t) = A sin(ωt) + B cos(ωt) and ω² = k/m, where k is the spring constant. The challenge lies in determining the spring constant k and the angular frequency ω to find the displacement after 0.42 seconds.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Knowledge of mass-spring systems
  • Familiarity with the equations of motion for oscillating systems
  • Ability to calculate angular frequency (ω) and spring constant (k)
NEXT STEPS
  • Calculate the spring constant k using Hooke's Law (F = kx)
  • Learn how to derive angular frequency (ω) from k and mass (m)
  • Practice solving SHM problems using the equation x(t) = A sin(ωt) + B cos(ωt)
  • Explore the concept of amplitude in harmonic motion and its impact on displacement
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Students studying physics, particularly those focusing on mechanics and oscillations, as well as educators seeking to clarify concepts related to mass-spring systems and simple harmonic motion.

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A mass on a spring, trying to find dispacement after at certain time. (Please Help!)

Homework Statement



A 0.27 kg mass is suspended on a spring that stretches a distance of 4.9 cm. The mass is then pulled down an additional distance of 12.5 cm and released. What's the displacement from the equilibrium position with the mass attached (in cm) after 0.42 s? Take up to be positive and use g = 9.81 m/s^2

m=.27kg
t=.42s
g=9.81m/s^2
I don't know how to represent it, but I believe that 4.9 is the equilibrium.
12.5cm is the initial displacement (maybe x0?)

Homework Equations



I have no idea, this is what I need help with.

maybe u=1/2kx^2, but I don't have a k, and I don't need u, but it is the only spring equation I know

The Attempt at a Solution

 
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I also found the fallowing equations dealing with harmonic oscillation:
<br /> <br /> x(t)=A\sin(\omega t)+B\cos(\omega t)<br /> <br />
<br /> <br /> \omega^2 =\frac{k}{m}<br /> <br />
i'm not sure what the w is
 


ooh, and this one look very promissing:

[ctex]

x(t)=\frac{v_0}{\omega}\sin(\omega t)+x_0\cos(\omega t)\;.

[/ctex]

I know that v0 is 0 so that wipes out the first half, I think x0 is 12.5, but where does the 4.9 come in and what is the w?

hmm, the image doesn't seem to work so I'm going to try writing it out:

x(t)=((v0)/w)sin(wt) + (x0)cos(wt)
 


The stretching force is mg = -kx. Find k.
When you stretch the spring further and release, it will execute a simple harmonic motion with amplitude A and angular frequency ω =sqrt(k/m)
Can you write the equation of SHM and find x at a given time?
 

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