A new thought and a problem |P(A)| = 1?

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Homework Help Overview

The discussion revolves around the properties of the power set P(A) and the empty set, particularly focusing on the cardinalities |A| and |P(A)| when A is the empty set. Participants are exploring the definitions and implications of these concepts in set theory.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand why |P(A)| equals 1 when A is the empty set, despite the empty set being defined as containing no elements. Questions are raised about the nature of the empty set as a subset and the interpretation of cardinality in this context.

Discussion Status

The discussion is active, with participants providing clarifications on the definitions of the empty set and its properties. Some guidance has been offered regarding the notation and the reasoning behind the cardinality of the power set, though multiple interpretations of the empty set's significance are being explored.

Contextual Notes

There are mentions of notation confusion, particularly with LaTeX representations of the empty set and power set, which may affect understanding. The original poster expresses uncertainty about the symbols used in their textbook.

flyingpig
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Homework Statement

P(A) = power set of A (in my book it is funky looking P, someone tell me how to read it and what it is)

What is |A| and |P(A)|?

a) A = [tex]\o[/tex]

Book say that

|A| = 0, and |P(A)| = 1

Why?

P(A) = {\o} I know that this is one thing (or one element), but the symbol represents empty set meaning nothing so

{\o} = {{no elements}} = {}

SO Why isn't |P(A)| = 0?

EDIT: \o is supposed to be that symbol that looks like the greek letter phi, but I don't know why it isn't showing
 
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You can also write phi as {}. {} contains no elements. It's the empty set. |{}| means the number of elements in {}. That's 0. P({}) is the set of all subsets of {}. There's only one, {}. So P({})={{}}. It contains one element {}. So |{{}}|=1.
 
Do you mean this [itex]\mathcal{P}[/itex] ? use \mathcal{P}

For [itex]\emptyset\,,[/itex] use \emptyset, although, \o does work for some implementations of LaTeX.
 
SammyS said:
Do you mean this [itex]\mathcal{P}[/itex] ? use \mathcal{P}

For [itex]\emptyset\,,[/itex] use \emptyset, although, \o does work for some implementations of LaTeX.

Yes thank you lol, now I am wondering the heck is \o lol
 
Dick said:
You can also write phi as {}. {} contains no elements. It's the empty set. |{}| means the number of elements in {}. That's 0. P({}) is the set of all subsets of {}. There's only one, {}. So P({})={{}}. It contains one element {}. So |{{}}|=1.

But {} is nothing
 
Actually why is the empty set is a subset of A anyways?
 
flyingpig said:
But {} is nothing
It's not nothing. It's a set containing no elements. You can't just erase the curly brackets willy-nilly.
flyingpig said:
Actually why is the empty set is a subset of A anyways?
It's because it's true that every element of the empty set is an element of A. Or to put it in a way that may be a little clearer, {} doesn't contain an element that is not also in A.
 
flyingpig said:
Actually why is the empty set is a subset of A anyways?

Try it this way. The empty set is like a bookcase containing no books. It's not nothing, it's still a bookcase.
 

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