A part in a solution for exercise 1.24 from Atiyah-MacDonald

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SUMMARY

The discussion centers on the proof of the equality ##a \vee (b \wedge c) = (a \vee b) \wedge (a \vee c)## in the context of Boolean rings. It highlights the property that in a Boolean ring, the equation ##a^2 = a## leads to the conclusion that ##2x = 0## for any element x. This property is crucial for simplifying the expression ##2ac + 2ab + 2abc = 2a \wedge (b \vee c)##, which is a key step in the proof. The confusion between rings, algebras, and lattices is acknowledged, emphasizing the importance of understanding these structures in abstract algebra.

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  • Understanding of Boolean rings and their properties
  • Familiarity with basic algebraic structures: rings, algebras, and lattices
  • Knowledge of the operations and identities in Boolean algebra
  • Ability to manipulate algebraic expressions involving Boolean variables
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  • Study the properties of Boolean rings in detail
  • Explore the differences between rings, algebras, and lattices
  • Learn about the implications of the identity ##a^2 = a## in various algebraic structures
  • Investigate additional proofs involving Boolean algebra and its applications
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mad mathematician
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In the part below where the author of this solution, wants to show that: ##a\vee (b\wedge c)=(a\vee b)\wedge (a\vee c)##, in the third equality he adds ##2ac+2ab+2abc=2a\wedge(b\vee c)##; can someone explain to me why can we do this here?
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Thanks!
 
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In a Boolean ring ##a^2=a##, so ##2x=(2x)^2=4x^2=4x##, therefore ##2x=0##.
 
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Yes, I forgot about it.
Got confused between rings,algebras and lattices... :oldbiggrin:
 

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