A particle of mass m moves in a one dimensional potential

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SUMMARY

A particle of mass m moves in a one-dimensional potential defined by U(x) = A|x|³, where A is a constant. The time period T of the particle's motion is inversely related to the total energy E through the equation T = E - 1/k. To find the value of k, one must integrate the velocity expression v = √(2/m)(E - A|x|³) and determine the limits of integration based on the turning points where the potential energy equals the total energy.

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1.The problem, statement, all variables and given/known data

A particle of mass m moves in a one dimensional potential U(x)=A|x|3, where A is a constant. The time period depends on the total energy E according to the relation T=E-1/k
Then find the value of k.

2. Homework Equations


V=dx/dt
E=kinetic energy + U
F=-dU/dx

The Attempt at a Solution



##E=\frac{1}{2}mv^2+a|x|^n##
##v=\sqrt{\frac{2}{m}(E-a|x|^n)}##
##dt=\frac{dx}{v}##
Integrating LHS, I can get the time period. But when integrating RHS, how do I find the limits?
 
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The particle moves between the turning points, where its velocity becomes zero, that is, the potential energy is equal to the total energy E.
 
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