A PC software similiar to TI-89 ?

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farhadd
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Hi all,

I am particularly looking for a program able to compute a phasor expression, and also able to compute complex trigonometry.

in TI-89, one can easily input phasors like :

(1<3) + (1<5) =

or:

Sinh(3+4i) =

And the calculator gives the answer. is there a software for PC, that can do the same operations as easily?
 
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Not sure what you are asking and it is not a PC software, but have you checked Woflram alpha?
 
A tool for computing Phasor algebra?

Mods sorry for the double-thread, this would be the right sub-forum I guess

I am particularly looking for a program able to compute a phasor expression, and also able to compute complex trigonometry.

in TI-89, one can easily input phasors like :

(1 <3 degree) + (10 <5 radian) =


And the calculator gives the answer. is there a software for PC, that can do the same operations as easily?

Someone already pointed me to Wolfram Alpha, which works great. but it's an online tool. Is there an offline tool for this, and also is any of the CAS systems available (other than TI's), able to input data as phase and magnitude?
 
farhadd said:
Mods sorry for the double-thread, this would be the right sub-forum I guess

(Two threads merged)
 
There may be a better solution, but Mathematica might work for you.
Define 3 new user level functions:
CircleDot[r_,a_]:=r Cos[a]+I*r Sin[a]; (* to enter a phasor *)
CirclePlus[x_,y_]:=ComplexExpand[x+y]; (* to add phasors *)
CircleTimes[x_,y_]:=ComplexExpand[x*y]; (* to multiply phasors *)

Note: From the keyboard Esc c. Esc gives you CircleDot, Esc c+ Esc CirclePlus and Esc c* Esc CircleTimes. On the screen in Mathematica those then turn into little circles with a . + or x inside to look somewhat like ordinary operators. (Here I'll cheat on the next line and just write c. c+ and c* instead)

1 c. (Pi/4) c+ 2 c. (120 Degree) c* 3 c. (45 Degree)
then gives
-3 Sqrt[3/2]-Sqrt[2]+I(3 Sqrt[3/2]-Sqrt[2])
and
N[%]
then gives
-5.08845 + 2.26002 I

Sinh[3+4I] gives Sinh[3+4I], as the TI calculator should, while
N[%]
gives
-6.54812 - 7.61923 I

Is that close enough to satisfy what you need?

Can anyone else improve this even further or think of a better product?
 
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