A plane and a point and another point

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SUMMARY

The discussion addresses a mathematical problem involving a plane defined by the equation x+y+z=18 and a point A=(1,1,1) representing an explosion's origin. The solution involves calculating the intersection point P of the line through A and the plane, resulting in P=(6,6,6). Additionally, the distance D between point A and point P is computed using the distance formula, yielding a result of D=8.66. The calculations confirm the correct approach to finding the perpendicular distance from point A to the plane.

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[SOLVED] A plane and a point and another point

Homework Statement



According to the Flat Earth CLub, Earth is a plane described by the equation
x+y+z = 18
Also according to the Flat Earth Club, Earth will be destroyed on the day this assignment is due by an explosion that will spontaneously occur at the so-called "armageddon point" A = (1,1,1). It so happens that the school (considered as a point) will be the first place on Earth that is destroyed by this explosion (how sad)



Homework Equations



a) Calculate the coordinates of the school.
b)What is the distance between A and the school. What is the distance between A and Earth?


The Attempt at a Solution



a. Form the line that passes through point A with a direction vector that is parallel to the normal vector of the plane.
L: (x,y,z) = (i + j + k) + (i + j + k)t
= (1 + t)i + (1+t)j + (1+t)k
Now substitute into the equation of the plane to determine the point of intersection P.
x = t + 1
y = t +1
z = t + 1
(t+1) + (t+1) + (t +1 ) = 18
3t + 3 = 18
3t = 15
t = 5
The point P is then (6, 6, 6)



b. The distance (D) between A and the Earth/Monash Universtiy (P) which are 3-D points, is calculated by:

D = √[(px-ax)2 + (py-ay)2 + (pz-az)2]

Where P = (px, py, pz) and A = (ax, ay, az)
Therefore: P = (6,7,8) and A = (1,1,1) and
D= √[(6-1)2 + (6-1)2 + (6-1)2
= √75
= 8.66
 
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Is your question about this whether you solved it correctly? I believe the answer is 'yes'. You are basically being asked to find the perpendicular distance from A to the place and the point on that plane where the normal line from A meets the plane. And that is just what you have done...
 

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