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A Pretty Basic Work/Energy Question

  1. Apr 13, 2013 #1
    1. The problem statement, all variables and given/known data

    A man pushes on a 30.0kg crate 4.50 meters at a constant velocity. The floor has a coefficient of kinetic friction of 0.250. How much work does the man's force do on the crate.

    2. Relevant equations

    W = F*d, ƩFx = F(push) - F(friction) = 0

    3. The attempt at a solution

    W = F*d, where F = 0.25*30.0kg*9.81m/s^2*4.50m

    W = 331 joules

    My book has 333 joules, is my book wrong? If not, where are they getting the extra joules?
     
  2. jcsd
  3. Apr 13, 2013 #2

    cepheid

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    Gold Member

    I don't see anything wrong with your method. Maybe the book answer is a typo or a rounding error of some kind?
     
  4. Apr 13, 2013 #3
    Thanks for your opinion.
     
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