A Pretty Basic Work/Energy Question

[student34]

Homework Statement

A man pushes on a 30.0kg crate 4.50 meters at a constant velocity. The floor has a coefficient of kinetic friction of 0.250. How much work does the man's force do on the crate.

Homework Equations

W = F*d, ƩFx = F(push) - F(friction) = 0

The Attempt at a Solution

W = F*d, where F = 0.25*30.0kg*9.81m/s^2*4.50m

W = 331 joules

My book has 333 joules, is my book wrong? If not, where are they getting the extra joules?

 

[cepheid]

I don't see anything wrong with your method. Maybe the book answer is a typo or a rounding error of some kind?

 

[student34]

I don't see anything wrong with your method. Maybe the book answer is a typo or a rounding error of some kind?

Thanks for your opinion.