1. Problem Statement: A worker lifts a heavy crate vertically 1.0 m in 2.0 s. If she lifts the same crate the same distance in 1.0 s, the work was done by her is A the same. B two times as great. C half as great. D four times as great. E one-fourth as great. F zero. 2. Relevant equations delta x=a.t^2/2+v0.t Fnet=ma Weight=mg W=F.d g=9.8N/kg 3. The attempt at a solution v0=0m/sec delta x=a.t^2/2 t=2sec 1=a.4/2 a=0.5m/sec^2 F=m(0.5+9.8)=10.3m N W=10.3m J t=1sec 1=a1/2 a=2 m/sec^2 F=m(2+9.8)=11.8m N W=11.8m J then work change. How the correct answer stays the SAME I didn't get it.