A problem in Real Analysis/Topology

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The discussion revolves around proving properties of a non-empty subset A of ℝ, where both A and its complement are open. It is established that A cannot be bounded above, as assuming it has a supremum leads to a contradiction with A being open. The second part involves showing that a subset B of A, defined by elements less than or equal to a point in the complement, is non-empty and has a lower bound. The conversation also touches on the implications of limit points and the nature of open sets in relation to the supremum. Ultimately, the conclusion drawn is that A must equal ℝ, reinforcing the interconnectedness of the properties discussed.
  • #31
vela said:
Why are you saying ##m## is inf(B)? The problem statement only says to show that ##m## bounds B from below and is greater than or equal to ##x##. It's not necessarily the greatest lower bound.

Wow I'm really sorry that's another typo the problem statement says to show that B has a and inferior bound not just a lower bound. Hence why I proceeded like that. Is my reasoning correct?
 

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