A Projectile motion problem, I .

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A cannon fires two shells at different angles, with the first at π/3 and the second at π/4, both at a velocity of 250 m/s. The problem requires finding the time interval between firings that leads to the shells colliding in the air, neglecting air drag. The time of flight for each shell can be calculated using the equation t=(2usinθ)/g, and the range can be determined with R=(u^2sin2θ)/g. A proposed method involves equating the time of flight of the two shells to find the interval, but clarification is needed as the goal is to determine the time until they collide, not just when they hit the ground. The book suggests the time interval is 11 seconds, indicating a specific solution to the problem.
a.ratnaparkhi
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Homework Statement


A cannon fires successively two shells with velocity u=250 m/s;the first at angle \theta1=\pi/3 & the second shell at an angle \theta2=\pi/4 to the horizontal, the azimuth being same. Neglecting air drag, find the time interval between firings leading to colling of shells.


Homework Equations


range R=(u^2sin2\theta)/g
Time of flight t=(2usin\theta)/g

The Attempt at a Solution


I'm really confused &unable to figure out.
Book says that its 11s.
 
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Find the horizontal distance where the two bodies collide by solving there equations. From this, you can get time of flight of two bodies from projection to collision and what you need..?
 
I thought, if we assume the required time interval 't' and time of flight of two shells T1& T2 respectively, then after equating T1+t=T2, 't' can be easily found.
 
a.ratnaparkhi said:
I thought, if we assume the required time interval 't' and time of flight of two shells T1& T2 respectively, then after equating T1+t=T2, 't' can be easily found.

No...that would be the time between firings to get the shells to hit the ground simultaneously.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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