2 Projectiles are fired simultaneously

  • Thread starter Thread starter Om Swostik
  • Start date Start date
  • Tags Tags
    Projectiles
Click For Summary

Homework Help Overview

The problem involves two projectiles fired simultaneously from ground level with the same initial speed, both covering the same horizontal distance of 160 meters. One projectile reaches the ground 6 seconds before the other, with gravitational acceleration being the only force acting on them. The goal is to calculate the initial speed.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the angles of projection for the two projectiles, suggesting one is at angle theta and the other at 90 - theta. They equate the range and time of flight, noting the time difference of 6 seconds. Some express difficulty in solving the resulting equations due to limited knowledge of trigonometry.

Discussion Status

The discussion is ongoing, with participants sharing their attempts to set up equations based on the problem's conditions. There is a request for others to share their working to identify potential mistakes, indicating a collaborative effort to explore the problem further.

Contextual Notes

Participants mention the need for clarity on the equations used and the importance of sharing their working steps, reflecting the forum's collaborative learning environment.

Om Swostik

Homework Statement


2 projectiles are fired simultaneously from ground level with same initial speed (u).Both cover same horizontal distance of 160m on reaching the ground level .One of them reaches 6 sec prior to the other.Only gravitational acceleration g=10m/s squared governs the motion of both the projectile.Calculate u.[/B]

Homework Equations


Range(horizontal distance)=u squared sin 2×theta/g= Ux cos theta ×time
Time=2u sin theta/g
Where ,
U is initial velocity
Theta is the angle of projection
and T is the time taken by the projectile to reach ground level.
Note:vector u has 2 components which are Ux=u cos theta and Uy=u sin theta

The Attempt at a Solution

 
Physics news on Phys.org
Om Swostik said:

Homework Statement


2 projectiles are fired simultaneously from ground level with same initial speed (u).Both cover same horizontal distance of 160m on reaching the ground level .One of them reaches 6 sec prior to the other.Only gravitational acceleration g=10m/s squared governs the motion of both the projectile.Calculate u.[/B]

Homework Equations


Range(horizontal distance)=u squared sin 2×theta/g= Ux cos theta ×time
Time=2u sin theta/g
Where ,
U is initial velocity
Theta is the angle of projection
and T is the time taken by the projectile to reach ground level.
Note:vector u has 2 components which are Ux=u cos theta and Uy=u sin theta

The Attempt at a Solution

An attempt is required. Forum rules.
 
  • Like
Likes   Reactions: jfnn
THE ATTEMPT AT A SOLUTION:
I took the angle of projection of 1st projectile as theta and the angle of the 2nd one as 90 - theta (as there can be two angles of projection for the same range).
I equated the range and the time ,that is
T=t+6.As I have really limited knowledge of trigonometry, the resulting equation which I arrived at couldn't be solved by me.
 
Om Swostik said:
THE ATTEMPT AT A SOLUTION:
I took the angle of projection of 1st projectile as theta and the angle of the 2nd one as 90 - theta (as there can be two angles of projection for the same range).
I equated the range and the time ,that is
T=t+6.As I have really limited knowledge of trigonometry, the resulting equation which I arrived at couldn't be solved by me.
Please post the equation. It might save time to post your working too, in case you have a mistake somewhere.
 

Similar threads

  • · Replies 38 ·
2
Replies
38
Views
2K
Replies
40
Views
3K
Replies
17
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
27
Views
3K
Replies
55
Views
6K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
40
Views
8K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
2K