A question about mean value theorem

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SUMMARY

The discussion focuses on applying the Mean Value Theorem (MVT) to the piecewise function defined as f(x) = {2x³ - x + 1 for x ∈ [0,1], 3x² - x for x ∈ (1,3]}. The user seeks to find the point(s) c where the slope of the tangent equals the slope of the chord. Two solutions were proposed: c = 13/9 and c = 2 or c = 1/(√3). The user confirms that multiple points can yield the same slope, aligning with MVT principles.

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Homework Statement


hello ,
if f(x) is a function which satisfies the mean value theorem , where :-
[tex]f(x) = \left\{ {\begin{array}{*{20}c}<br /> {2x^3 - x + 1\quad \quad x \in [0,1]} \\<br /> {3x^2 - x\quad \quad \quad x \in (1,3]} \\<br /> \end{array}} \right.[/tex]

find the value of (c) by using the mean value theorem , where (c) is the points in which the slope of tangent is equal to the slope of chord .
I want the steps of the solution please .



Homework Equations





The Attempt at a Solution


i solve with some method and find that c=13/9
and I solve with other method and find that c=2 or c=1/(sqrt 3)



very thanks >>
 
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What method did you try to solve it with? How did you come up with those two solutions? Please show us what you've done...
 
It is not forbidden that in more than 1 point they have the same slope.
 

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