A Question About Partial Derivatives

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SUMMARY

The discussion centers on the mathematical relationship between partial derivatives in the context of classical mechanics, specifically regarding the kinetic energy expression T = 1/2 Σ m_i v_i². Participants explore the validity of the assumption that ∂v_i/∂dot{q}_k = ∂x_i/∂q_k. The key insight is that the relationship holds true due to the chain rule, where ∂x_i/∂q_k can be expressed as ∂x_i/∂t * ∂t/∂q_k, leading to the conclusion that v_i = ∂x_i/∂t/∂q_i. This confirms the equivalence of the two partial derivatives under the given conditions.

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Maor Hadad
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Homework Statement


v_{i}=\dot{x}_{i}=\dot{x}_{i}\left(q_{1},q_{2},..,q_{n},t\right)
T \equiv \frac{1}{2}\cdot{\sum}m_{i}v_{i}^{2}
\frac{\partial T}{\partial\dot{q}_{k}}={\sum}m_{i}v_{i}\frac{\partial v_{i}}{\partial\dot{q}_{k}}={\sum}m_{i}v_{i}\frac{\partial x_{i}}{\partial q_{k}}[/B]

Homework Equations


Why is it ok to assume:
\frac{\partial v_{i}}{\partial\dot{q}_{k}} = \frac{\partial x_{i}}{\partial q_{k}}

The Attempt at a Solution


I can say that:
\frac{\partial x_{i}}{\partial q_{k}}=\frac{\partial x_{i}}{\partial t}\frac{\partial t}{\partial q_{k}}=\frac{v_{i}}{\dot{q_{i}}} but it's not the same as written.

and the expression \frac{\partial v_{i}}{\partial\dot{q}_{k}} says to differentiate the velocity according to change of the q quardinate in time.
 
Last edited:
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Maor Hadad said:

Homework Statement


v_{i}=\dot{x}_{i}=\dot{x}_{i}\left(q_{1},q_{2},..,q_{n},t\right) T \equiv \frac{1}{2}\cdot{\sum}m_{i}v_{i}^{2} \frac{\partial T}{\partial\dot{q}_{k}}={\sum}m_{i}v_{i}\frac{\partial v_{i}}{\partial\dot{q}_{k}}={\sum}m_{i}v_{i}\frac{\partial x_{i}}{\partial q_{k}}
2. Homework Equations [/B]
Why is it ok to assume:\frac{\partial v_{i}}{\partial\dot{q}_{k}} = \frac{\partial x_{i}}{\partial q_{k}}

The Attempt at a Solution


I can say that: \frac{\partial x_{i}}{\partial q_{k}}=\frac{\partial x_{i}}{\partial t}\frac{\partial t}{\partial q_{k}}=\frac{v_{i}}{\dot{q_{i}}} but it's not the same as written.

and the expression \frac{\partial v_{i}}{\partial\dot{q}_{k}} says to differentiate the velocity according to change of the q quardinate in time.
Maybe try:
##\displaystyle \frac{\partial x_i}{\partial t}=\frac{\partial x_i}{\partial q_k} \frac{\partial q_k}{\partial t} ##​
 

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