A question about Transcendental numbers

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The discussion centers around the definition and properties of transcendental numbers, specifically addressing a misconception about their existence. A transcendental number, by definition, cannot be a solution to any polynomial equation with rational coefficients. The confusion arises from the assumption that if a transcendental number \( m \) can be expressed in terms of polynomial equations, it must not exist. Participants clarify that transcendental numbers do exist and are distinct from algebraic numbers, which can be roots of such equations.

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  • Understanding of polynomial equations and their coefficients
  • Familiarity with the definitions of transcendental and algebraic numbers
  • Basic knowledge of complex and real numbers
  • Concept of rational coefficients in mathematics
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ShayanJ
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hi pals
assume that m is a Transcendental number.
as you know we have:
x-m=0 => x=m
x^2-m=0 => x=+ or - sqrt(m)
.
.
.
so there must not be even one Transcendental number.
because all complex and real numbers can be the zero(s) of the equations above.
where is the problem?
thanks
 
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A http://en.wikipedia.org/wiki/Transcendental_number" is, by definition, not the zero of a polynomial with rational coefficients.
 
Last edited by a moderator:
Shyan said:
isn't 1 rational ?

The constant term of the polynomial, in you case m, is also considered a coefficient (of x^0).
 
Shyan said:
hi pals
assume that m is a Transcendental number.
as you know we have:
x-m=0 => x=m
x^2-m=0 => x=+ or - sqrt(m)
.
.
.
so there must not be even one Transcendental number.
because all complex and real numbers can be the zero(s) of the equations above.
where is the problem?
thanks
Do you understand the definition of "transcendental number"? A transcendental number is one that cannot be found as a solution to a polynomial equation with integer coefficients. Saying that "x= + or - sqrt{m}" says nothing about whether x satisfies a polynomial equation with integer coefficient.
 
oh people really excuse me
i understand it now.
sorry for interrupting you
 

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