A question about Transcendental numbers

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Discussion Overview

The discussion revolves around the concept of transcendental numbers, specifically questioning the implications of their definitions in relation to polynomial equations. Participants explore the nature of transcendental numbers and their relationship to rational coefficients in polynomials.

Discussion Character

  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant asserts that if m is a transcendental number, then it leads to the conclusion that there cannot be any transcendental numbers, based on the equations presented.
  • Another participant clarifies that a transcendental number is defined as one that is not a solution to any polynomial equation with rational coefficients.
  • A participant questions the rationality of the number 1 in the context of polynomial coefficients.
  • Further clarification is provided that the constant term of a polynomial, such as m, is indeed considered a coefficient.
  • A later reply emphasizes the definition of transcendental numbers, stating that they cannot be solutions to polynomial equations with integer coefficients, challenging the earlier reasoning.
  • One participant expresses understanding after the discussion, indicating a shift in their perspective.

Areas of Agreement / Disagreement

Participants do not reach a consensus, as there are competing views regarding the implications of transcendental numbers and their definitions. Some participants challenge the initial reasoning while others seek clarification.

Contextual Notes

There are limitations in the discussion regarding the definitions of transcendental numbers and the nature of polynomial equations, which remain unresolved. The distinction between rational and integer coefficients is also a point of contention.

ShayanJ
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hi pals
assume that m is a Transcendental number.
as you know we have:
x-m=0 => x=m
x^2-m=0 => x=+ or - sqrt(m)
.
.
.
so there must not be even one Transcendental number.
because all complex and real numbers can be the zero(s) of the equations above.
where is the problem?
thanks
 
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A http://en.wikipedia.org/wiki/Transcendental_number" is, by definition, not the zero of a polynomial with rational coefficients.
 
Last edited by a moderator:
Shyan said:
isn't 1 rational ?

The constant term of the polynomial, in you case m, is also considered a coefficient (of x^0).
 
Shyan said:
hi pals
assume that m is a Transcendental number.
as you know we have:
x-m=0 => x=m
x^2-m=0 => x=+ or - sqrt(m)
.
.
.
so there must not be even one Transcendental number.
because all complex and real numbers can be the zero(s) of the equations above.
where is the problem?
thanks
Do you understand the definition of "transcendental number"? A transcendental number is one that cannot be found as a solution to a polynomial equation with integer coefficients. Saying that "x= + or - sqrt{m}" says nothing about whether x satisfies a polynomial equation with integer coefficient.
 
oh people really excuse me
i understand it now.
sorry for interrupting you
 

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