A second order nonlinear ordinary differential equation

  • Thread starter Lightfuzz
  • Start date
  • #1
Lightfuzz
15
0
How, if possible, could I solve the equation: x''x=((x')^2)/2? Thanks.
 

Answers and Replies

  • #2
Filip Larsen
Gold Member
1,609
531
If you are allowed to guess, then try guess a very often used function that when differentiated gives a scaled version of itself, i.e. a function that satisfy x' = a x, with a being a constant.
 
  • #3
hamster143
908
2
Try to find such a pair of real numbers a & b that d/dt (x^a x'^b) is proportional to x"x-((x')^2)/2.
 
  • #4
Lightfuzz
15
0
If you are allowed to guess, then try guess a very often used function that when differentiated gives a scaled version of itself, i.e. a function that satisfy x' = a x, with a being a constant.

I've tried that but is there a way to actually solve it without guessing?
 
  • #5
phyzguy
Science Advisor
5,054
2,054
Equations like this, which do not contain the independent variable, are called autonomous systems. They are easily solved with the substitution x'' = x' dx'/dx . Then collect the terms in x' and x and integrate them both. This will give you x' in terms of x, which you can then integrate a second time.
 
  • #6
Phrak
4,265
2
Do you only require a numerical solution given some particular boundry conditions?
 
  • #7
gato_
116
0
rearrange:

[tex] \frac{1}{2x}=\frac{\ddot{x}}{x}=-\frac{d}{dx}(\frac{1}{\dot{x}}) [/tex]

Then, reduce to a quadrature:

[tex]dt=(C-ln(\sqrt{x}))dx =d[x(C'-ln(\sqrt{x}))] [/tex]
 

Suggested for: A second order nonlinear ordinary differential equation

Replies
2
Views
228
Replies
4
Views
1K
  • Last Post
Replies
3
Views
1K
Replies
7
Views
802
Replies
1
Views
406
Replies
10
Views
1K
Replies
3
Views
774
Replies
12
Views
1K
  • Last Post
Replies
1
Views
712
Top