A ship going upstream and experiences a frictional force

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SUMMARY

The discussion centers on calculating the optimal speed (V) of a ship traveling upstream against a current (U) while minimizing energy consumption. The frictional force (F_r) experienced by the ship is defined as F_r = cV^2, where c is a constant. Participants clarify that the power required (P) to maintain position against the current is equivalent to the power needed to move upstream, expressed as P = F_r x U = cU^3. The distinction between power to remain stationary and to move forward is deemed unnecessary, as both require the same energy input.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Familiarity with power calculations in physics
  • Knowledge of frictional forces and their mathematical representation
  • Basic algebra for manipulating equations
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  • Study the principles of fluid dynamics in relation to ship movement
  • Learn about power and energy consumption calculations in marine engineering
  • Explore the effects of frictional forces on moving objects in water
  • Investigate optimization techniques for minimizing energy use in transportation
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Marine engineers, physics students, and anyone involved in optimizing vessel performance against currents will benefit from this discussion.

fara0815
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Hello there!

This problem is giving me a hard time and I thought maybe one of you could give me a hint:

"A ship is going upstream with a constant power P. Its speed [tex]V[/tex] is relative to the water and the water's speed [tex]U[/tex] is relative to the shore. The ship needs tp overcome a frictional force of [tex]F_r=cv^2[/tex] caused by the water which depends on its relativ speed. How big does v have to be so that the ship goes from A to B with the lowest energy consumption?"

Where I would start is that the ship needs at least the power which is neccesary to stay in the same place. Which would be
[tex]P=F_r x U = cU^2U=cU^3[/tex] and than in addition some extra power to go upstream. That would be [tex]P=F_r x (v-u)=c(V-U)^2 x (V-U)[/tex]. But from here, if it's really correct, I do not know how to continue :(
 
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I assume the "x" in your formula is a multiplication sign. Don't do that, it's confusing. Just [itex]P= F_rU[/itex] would be sufficient.
I don't believe you can or should distinguish between the power necessary to "stand still" and the power necessary to move forward against the current. They are the same. Note also that U is speed of the boat relative to the water so it makes no sense to use V-U (which would be negative: if the boat is moving forward against the current, U> V).
 

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