- #1

gipc

- 69

- 0

say we have the function

f=xz +x'z'

why is this equals (x xor z)' ?

i thought using De-Morgan's law we shall get

(x xor z)'=(x'z+z'x)'=(xz'zx')=0

then why does (x xor z)'=xz+x'z' ?

and one more small thing,

say we have

(x xor y) xor (x xor z)'

why does (x xor y) xor (x xor z)' = (x xor y xor x xor z)'

how did they come to this term?