A small problem with complex conjugations

  • Context: High School 
  • Thread starter Thread starter Parnpuu
  • Start date Start date
  • Tags Tags
    Complex
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
Parnpuu
Messages
24
Reaction score
0
Hi!

I have a problem with understanding an equation which is really simple.

zz*=(a2+b2)

shouldn't there be an i there if

z1z2=(a1+ib1)(a2+ib2)

is the equation correct?

If it is could someone explain to me why there is no imaginary number?

Thank You!
 
Physics news on Phys.org
if z = a + bi, then z* (conjugate of z) = a - bi so

(z)(z*) = (a+bi)(a-bi) = a2 - (bi)2 = a2 -(i)2b2 = a2 -(-1)b2 = a2 + b2
 
Yes I can see that now.

Thanks!