A straight line in the complex plane

Click For Summary
SUMMARY

The discussion centers on the representation of complex numbers in the form of linear equations in the complex plane. Specifically, it examines the equations w = sz + tz* + r = 0 and w - w* = (s - t*)z + (t - s*)z* + r - r* = 0. Participants debate whether the latter equation also represents a complex straight line. The conclusion is that while w + w* can be expressed in the standard form of a complex straight line, w - w* introduces an imaginary component that complicates its classification as such.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with linear equations in the complex plane
  • Knowledge of conjugates and their implications in complex analysis
  • Ability to manipulate and expand complex expressions
NEXT STEPS
  • Study the properties of complex conjugates in equations
  • Learn about the geometric interpretation of complex numbers
  • Explore the concept of linear transformations in the complex plane
  • Investigate the conditions under which complex equations represent straight lines
USEFUL FOR

Mathematicians, students of complex analysis, and anyone interested in the geometric representation of complex equations will benefit from this discussion.

rajeshmarndi
Messages
319
Reaction score
0
Homework Statement
w+w* = (s+t*)z + (t+s*)z* + r+r* = 0, is a straight line. Then couldn't find how does
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0, is also a straight line.
Relevant Equations
w = sz+tz*+r=0
sz+tz*+r=0=say w

so w* = s*z* + t*z + r*=0

Now ,
w+w* = (s+t*)z + (t+s*)z* + r+r* = 0
= p*z + pz* + k = 0...eq(1) ( k is a constant or twice real part of w)
which is in complex straight line equation form i.e ab* + a*b + c = 0 ( a,b are complex number and c a real number.

Now, again,
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0

I couldn't understand, in the solution, how this is also termed as a complex straight line like eq(1).
Since when this is worked out, it comes to be as,

q*z - qz* + id = 0 ( since r-r* will give imaginary number)

This is not in the form of a complex straight line equation.

Thanks.
 
Physics news on Phys.org
rajeshmarndi said:
sz+tz*+r=0=say w

so w* = s*z* + t*z + r*=0

Now ,
w+w* = (s+t*)z + (t+s*)z* + r+r* = 0
= p*z + pz* + k = 0...eq(1) ( k is a constant or twice real part of w)
which is in complex straight line equation form i.e ab* + a*b + c = 0 ( a,b are complex number and c a real number.

Now, again,
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0

I couldn't understand, in the solution, how this is also termed as a complex straight line like eq(1).
Since when this is worked out, it comes to be as,

q*z - qz* + id = 0 ( since r-r* will give imaginary number)

This is not in the form of a complex straight line equation.

Thanks.

What, in plain language, is the statement of the problem? Is it "prove that w+w*=0 describes a straight line in the complex plane"? Is it something else? I cannot figure out what you want.
 
Ray Vickson said:
What, in plain language, is the statement of the problem?
I want to know,
given w= sz+tz*+r=0

Is
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0
also a complex straight line?

[edit: r,s,t are non-zero complex number and z=x+iy (x,y ε R) ]
 
Last edited:
rajeshmarndi said:
I want to know,
given w= sz+tz*+r=0

Is
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0
also a complex straight line?

[edit: r,s,t are non-zero complex number and z=x+iy (x,y ε R) ]

Write ##w## in real terms, and expand it out to see what you get. That is, write ##s=s_1+i s_2, t = t_1+i t_2, r = r_1+i r_2## and ##z = x + i y##.
 
Ray Vickson said:
Write ##w## in real terms, and expand it out to see what you get. That is, write ##s=s_1+i s_2, t = t_1+i t_2, r = r_1+i r_2## and ##z = x + i y##.
##w## becomes,

##w = [(s_1+t_1)x + (t_2-s_2)y] + i[(s_2+t_2)x + (s_1-t_1)y+r_2]=0##

So the real terms of ##w## is ## [(s_1+t_1)x + (t_2-s_2)y]=0##
 

Similar threads

Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
31
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K