A sum I wish I never came across

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In summary, the expression represents a limit as \Delta t and n approach 0 and infinity respectively, and the sum of x^k is taken. If x approaches 1^- and \Delta t approaches 0, the sum should diverge to positive infinity. However, if x is less than 1, the sum converges. The existence of interrelations between the variables may affect the limit's convergence.
  • #1
Apteronotus
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I've come across the following summation

[tex]lim_{\stackrel{\Delta t \rightarrow 0}{n \rightarrow \infty}}\left(\Delta t \sum_{k=0}^n x^k\right)[/tex]

moreover, as [tex]\Delta t \rightarrow 0, x\rightarrow 1^-[/tex]

Does the sum converge? to what?

My thoughts...
The sum as [tex]n \rightarrow \infty [/tex] is simply the Mclaren series of [tex](1-x)^{-1}[/tex], so as [tex]x \rightarrow 1^- [/tex], the sum should diverge to [tex]+ \infty[/tex], however, we have the [tex]\Delta t[/tex] in the front that [tex] \rightarrow 0[/tex], and that's as far as my intellect takes me...
any ideas?
 
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  • #2
dt doesn't seem to participate in the expression, did you forget it somewhere?
 
  • #3
elibj123 said:
dt doesn't seem to participate in the expression, did you forget it somewhere?

Yes, I'm so sorry. Its fixed now.
 
  • #4
You have three variables, n, x, and [itex]\Delta t[/itex].

If they are all allowed to vary independently, the limit does not exist - you can construct sequences of (n,x,[itex]\Delta t[/itex]) which approach any number you want.

If there are some interrelations between them, that's a different story.
 
  • #5
Apteronotus said:
My thoughts...
The sum as [tex]n \rightarrow \infty [/tex] is simply the Mclaren series of [tex](1-x)^{-1}[/tex], so as [tex]x \rightarrow 1^- [/tex], the sum should diverge to [tex]+ \infty[/tex], however, we have the [tex]\Delta t[/tex] in the front that [tex] \rightarrow 0[/tex], and that's as far as my intellect takes me...
any ideas?

if x < 1 it converges.
 

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