A Superball Colliding Inelastically with a Table

  • Thread starter Thread starter MirandaLeigh
  • Start date Start date
  • Tags Tags
    Table
Click For Summary
The discussion revolves around calculating the time-averaged force exerted by a table on a superball during an inelastic collision. The superball, with a mass of 50 grams, is dropped from a height and experiences a change in momentum, with values of Pbefore y at -0.27 kg*m/s and Pafter y at 0.22 kg*m/s. The impulse-momentum theorem is suggested as a method to find the average force, using the formula Fave = I/Δt, where I is the change in momentum and Δt is the collision duration of 15 ms. Participants express difficulty in identifying the correct equations to apply, particularly regarding the role of time in force calculations. The discussion emphasizes the need to apply the impulse formula to solve for the average force exerted during the collision.
MirandaLeigh
Messages
1
Reaction score
0

Homework Statement


As shown in the figure, a superball with mass M equal to 50 grams is dropped from a height of h1 . It collides with a table, then bounces up to a height of h2 . The duration of the collision (the time during which the superball is in contact with the table) is T=15ms . In this problem, take the positive y direction to be upward, and use g=9.8 for the magnitude of the acceleration due to gravity. Neglect air resistance.

previously in other parts of the problem I found that the y component of the momentum, of the ball immediately before the collision was Pbefore y =-0.27 kg*m/s and that the y component of the momentum of the ball after the collision was Pafter y=0.22 kg*m/s

I have to find the y component of the time-averaged force Favgy, in Newtons, that the table exerts on the ball


Homework Equations


I'm actually having problems figuring out what equations to use is all, the equations for force that my teachers given us for force don't use time, at least not yet.

The Attempt at a Solution


N/A Can't figure out the formula
 
Physics news on Phys.org
Use impulse (change in momentum) formula:

Fave = I/\Deltat

where I is the impulse i.e. final momentum minus initial momentum
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

Replies
2
Views
9K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
10
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 6 ·
Replies
6
Views
8K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
1
Views
2K
Replies
14
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K