Absolute & conditional convergence

Click For Summary

Homework Help Overview

The discussion revolves around determining the convergence properties of two series: one involving a variable \( n \) and the other involving \( x \). The participants are exploring absolute and conditional convergence, as well as divergence.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of the comparison test for the first series and consider whether the terms approach zero. For the second series, there is an exploration of absolute convergence by comparing it to a known convergent series.

Discussion Status

Some participants have provided insights regarding the convergence of the second series, suggesting it is absolutely convergent. However, there is uncertainty regarding the first series, with questions about its convergence or divergence still being explored.

Contextual Notes

There is a noted confusion between the variables \( n \) and \( x \) in the first series, which may affect the analysis. Additionally, the definition of convergence in terms of partial sums is mentioned as a relevant consideration.

magnifik
Messages
350
Reaction score
0

Homework Statement


Determine whether the series converges absolutely, conditionally, or not at all.

a) \Sigma (-1)nn4/(x3 + 1)

b) \Sigma sin(x)/x2


Homework Equations





The Attempt at a Solution


a) positive series is n4/n3+1 .. do i do comparison test ??

b) |sin(x)|/x2
compare it with 1/x2 which converges.. so it's absolutely convergent??
 
Physics news on Phys.org
You are kind of freely mixing n's and x's here. Are they supposed to be the same? If so, for the first one ask whether the nth term goes to zero. For the second one, yes, it's absolutely convergent.
 
woops, mixing up the n's & x's was a careless mistake
 
for a) the positive series diverges because n^4/n^3 + 1 goes to infinity, but I'm not sure if the original series converges or diverges
 
magnifik said:
for a) the positive series diverges because n^4/n^3 + 1 goes to infinity, but I'm not sure if the original series converges or diverges

A series whose terms don't go to zero diverges no matter what the signs on the terms. Look at the definition of convergence in terms of partial sums.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
7
Views
2K
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K