A 1.00m tall container is filled to the brim, partway with mercury and the rest of the way with water. The container is open to the amosphere. What must be the depth of the mercury so that the absolute pressure on the bottom of the container is twice the atmospheric pressure?
P2 = P1 + (rho)gh
The Attempt at a Solution
I know that the pressure at the bottom has to be 2*10^5 Pa, but I'm just not sure how to approach the rest of the problem. How do I deal with the split densities?