- #1

ScareCrow271828

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## Homework Statement

A 1m^3 steel cube is to be floated on mercury (specific gravity=13.6). On each side of the cube there is a 5mm clearance. Assume that the container is open to atmospheric pressure at 100kPA. Find the mass of the mercury.

## Homework Equations

P=F/A

## The Attempt at a Solution

I sum-mated the forces in the vertical direction and combined that with an equation for buoyancy. Then I solved for the height of the mercury around the cube, found the volume of the mercury and multiplied it by its density.

My question is: is it right to assume that atmospheric pressure has cancelling effects because it pushes down the steel cube but also pushes down the mercury which would push the steel cube back up? This makes sense conceptually to me, but I am having trouble understanding that since P∝1/A. It seems like by that equation atmospheric pressure would have different effects on the block and on the mercury.