Absolute value notation removal

Click For Summary

Homework Help Overview

The problem involves rewriting the inequalities involving absolute values, specifically |x| < 1 and |x| > 1, by eliminating the absolute value notation. The subject area pertains to inequalities and absolute value concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to rewrite |x| > 1 but is unsure of the correct form, suggesting a possible interpretation that is questioned by others. Participants discuss the implications of the inequalities and the relationship between the two cases.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's assumptions and exploring the logical structure of the inequalities. There is an emphasis on understanding the relationship between the two cases of absolute value and the nature of the statements involved.

Contextual Notes

Participants are encouraged to visualize the problem using a number line and consider the implications of the inequalities without reaching a definitive conclusion. The discussion is influenced by the need to clarify the logical connections between the statements.

kalpalned
Messages
2
Reaction score
0

Homework Statement


Rewrite |x| < 1 and |x| > 1 by eliminating the absolute value sign

Homework Equations


|x| < 1 = -1 < x < 1
|x| > 1 = ?

The Attempt at a Solution


I know that |x| < 1 can be rewritten as -1 < x < 1 but I'm not sure about |x| > 1. Am I right to assume that |x| > 1 = -1 > x > 1?
 
Physics news on Phys.org
kalpalned said:
|x| > 1 = -1 > x > 1?
Not quite.
kalpalned said:
|x| < 1 = -1 < x < 1
You did this one correctly.
If you can't think about |x|>1 separately,then you can use your previous answer to find this one.

Plot the number line.
Any number on this line will either satisfy:
|x|>1 or |x| <1
There can't be any number not falling into any of these 2 classes.
So,if a number ain't in the first class,it's surely going to be in the second class (neglecting x=1,of course).
Getting what to do now?
 
kalpalned said:
Am I right to assume that |x| > 1 = -1 > x > 1?
The way you have this written is that -1 is greater than x AND x is greater than 1. Is that even possible?
Remember when you negate an AND statement, like -1<x<1 which is read -1 is less than x AND x is less than 1, you will get an OR statement.
 
Thread closed, as a previous account of the OP's was permanently banned.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K