- #1

bailey89

- 2

- 0

## Homework Statement

Let R = { [ a + b*sqrt(m) c + d*sqrt(m) ] }

[ n(c - d*sqrt(m)) a - b*sqrt(m) ]

(Sorry if the matrix is unclear... I can't get it space nicely. r11 = a + b*sqrt(m) r12 = c + d*sqrt(m)

r21 = n(c -d*sqrt(m)) and r22 = a-b*sqrt(m) )

where a, b, c, d are elements of the rationals, and m, n elements of the integers, m and n not zero.

Show R is a division Ring if and only if the equation x^2 - m*y - n*z^2 +m*n*t = 0 has no other rationals solution except x = y = z = t = 0 ( The trivial solution.)

## Homework Equations

Going to use the determinant in the forward direction of the proof.

Possibly need linear independence.

A division Ring is simply a field without commutativity.( I know a lot of people call it a skew-field)

## The Attempt at a Solution

(====>)

So i working on the forward direction and the only way R is a division ring if that matrix is invertible.

So the determinant of that matrix would be a^2 - m*b^2 - (n*c^2 -n*d^2*m).

So we have a^2 -m*b^2 -n*c^2 +n*m*d^2 = 0. So i set it equal to 0.

(that equation looks pretty similar to the one I need.) So i guess i need to show that

a = b = c = d = 0 is the only rational solution. It seems i need to show a,b,c,d are linearly independent maybe but I am stuck but I feel its so close to being finished.

(<===) So assume the equation x^2 - m*y - n*z^2 +m*n*t = 0 has only the trivial solution. So we have a linear combination set equal to zero and the only solution is the trivial solution right?

So i guess then x, y, z, t are linearly independent? I am not sure where this is going to get me to that R is a division Ring I am really completely stuck on this one.