Abstract Algebra Homework Solution - Check Ring Homomorphism

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Homework Help Overview

The discussion revolves around verifying whether a given mapping is a ring homomorphism and exploring its properties as a monomorphism or epimorphism within the context of abstract algebra.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the definition of the mapping and its properties, questioning the surjectivity of the function and exploring the implications of the kernel being non-trivial. There are considerations about the nature of the range and whether it can encompass all real numbers.

Discussion Status

Some participants have provided insights into the nature of the mapping and its range, suggesting that the range is limited to specific forms. Others have raised questions about the implications of cardinality in relation to surjectivity, indicating a productive exploration of the topic.

Contextual Notes

There is an ongoing discussion about the assumptions regarding the codomain and the implications of the mapping being well-defined. Participants are also considering the relationship between the countability of the domain and the uncountability of the codomain.

NanoMath
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Homework Statement


Ring homomorphism.png


Hello guys
So I have the following problem, given the mapping above I have to check weather it's ring homomorphism, and
maybe monomorphism or epimorphism.

The Attempt at a Solution



So the mapping is obviously well defined, and I have proven it's homomorphism, and it's obviously not monomorphism because a polynomial P(x)= 5 - x2 is in the kernel so kernel is not trivial.
I am not sure how to prove if the function is surjective or not, obviously if the codomain were integers for every integers C , I could just use constant function p(x) = C and function would be surjective.
 
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NanoMath said:
I am not sure how to prove if the function is surjective or not

It is just an intuition, but I doubt there are polynomials of ##\mathbb{Z}[X]## such that ##p(\sqrt{5}) \in \mathbb{Q}-\mathbb{Z} ##.
 
Showing the map is a homomorphism shouldn't be too difficult. Simply show the map satisfies the properties of a homomorphism.

The rest of the question is asking if the map is also a bijection, or something more specific. Try applying the first isomorphism theorem if you know it, and use the fact that ##x^2 - 5## is the minimal polynomial.
 
NanoMath said:
I am not sure how to prove if the function is surjective or not, obviously if the codomain were integers for every integers C , I could just use constant function p(x) = C and function would be surjective.

Isn't it pretty obvious that the range is contained in the set ##a+b \sqrt{5}## where ##a## and ##b## are integers? Why isn't that all of ##R##?
 
I managed to show that function is not surjective with the hint that every element in the range is of the form ## a+b \sqrt{5} ## because for example ##\sqrt{2}## doesn't get hit by any element in domain. Is it also valid argument that function can't be surjective because ##\mathbb{R}## is uncountable whilst ##\mathbb{Z}[X]## is countable?
 
NanoMath said:
I managed to show that function is not surjective with the hint that every element in the range is of the form ## a+b \sqrt{5} ## because for example ##\sqrt{2}## doesn't get hit by any element in domain. Is it also valid argument that function can't be surjective because ##\mathbb{R}## is uncountable whilst ##\mathbb{Z}[X]## is countable?

Both of those arguments are good. The second makes it obvious if you know cardinality.
 

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